(x)=16x^2-2x-5

Solution for (x)=16x^2-2x-5 equation:

(x)=16x^2-2x-5

We move all terms to the left:

(x)-(16x^2-2x-5)=0

We get rid of parentheses

-16x^2+x+2x+5=0

We add all the numbers together, and all the variables

-16x^2+3x+5=0

a = -16; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-16)·5
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{329}}{2*-16}=\frac{-3-\sqrt{329}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{329}}{2*-16}=\frac{-3+\sqrt{329}}{-32}
$